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What mass of oxygen gas should react with 0.500 mol of propane at STP conditions?
C3H8
(g)+ 5 O2(g) ⇒ 3 CO2(g) + 4 H2O(g)
Since we already have the balanced equation, we'll find the mass of oxygen,
by starting with a mole to mole ratio
and finish by turning moles O2 into grams O2
0.500
moles C3H8
5 moles O2
/
1 mole C3H8
32.00 g O2
/
1 mole O2
= 80.00 g O
2
It will require 80.00 g O2 to completely react with 0.500 moles propane