Academic Subjects
Math
Algebra
Quadratic Equations
Completing The Square For x2 + 14x - 38

Solve by completing the square
x2 + 14x - 38



First, we want to set the equation equal to zero and
bring the constant to the other side of the equal sign

x2 + 14x - 38 = 0

x2 + 14x + ____ = 38


Next, divide the middle term by 2 and then square it

14 / 2
= 7          72 = 49


Add the squared value to both sides

x2 + 14x + 49 = 38 + 49

x2 + 14x + 49 = 87


Factor the perfect square you have created on the left side

(x + 7)2 = 87


and finally, solve for x

(x + 7)2 = 87

(x + 7)2 = ± 87

x + 7 = ± 9.33

x = ± 9.33 - 7

x1 = 9.33 - 7 = 2.33
x2 = - 9.33 - 7 = - 16.33