Academic Subjects
➤
Math
➤
Algebra
➤
Log Functions
➤
ln(e
0.4x
+ e
-0.4x
- 15)
Solve ln(e
0.4x
+ e
-0.4x
- 15)
Let's start by multiplying everything in the paranthesis by ln
(ln)e
0.4x
+ (ln)e
-0.4x
- (ln)15
just as a square root and something squared will cancel each other,
so will ln and e^
so let's start canceling
(ln)e
0.4x
+
(ln)e
-0.4x
- (ln)15
that leaves us with
0.4x + (-0.4x) - 2.71 = 0
0.4x + (-0.4x) = 2.71
0 x = 2.71
= no solution
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–8
M H
3
O
+
solution is ____?
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3
solution
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Make a buffer of pH = 5.20