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Chemistry
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General Chemistry
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Gases ➤
Volume Of Balloon After 28.8 Dry Ice Sublimation

A 28.8 g piece of dry ice is allowed to sublime into a large balloon.
Assuming that all of the carbon dioxide ends up in the balloon, what will the volume
of the balloon be at a temperature of 22℃ and a pressure of 742 mmHg



Applying the Ideal Gas Law, we first want to check if all units match
R 0.082057 L atm mol-1 K-1

Mercury

We'll have to convert temperature

22.00 °C + 273.15 = 295.15 K


pressure from mm Hg to atm

742 mm Hg =
1 atm / 760 mm Hg
= 0.976 atm


and turn grams into moles

28.8 g CO2 =
1 mole CO2 / 44.01 g CO2
= 0.6544 moles CO2

witchery &

Now, we're ready for pV = nRT

(0.976 atm)(L) = (0.6544 moles)
(0.082057 L atm) /             moles K
(295.15 K)

(0.976 atm)(L) = (15.84899 L atm)

L =
15.84899 L atm / 0.976 atm


L = 16.2387

chemistry

The balloon will have a volume of 16 L