Academic Subjects
➤
Chemistry
➤
General Chemistry
➤
Gases
➤
Finding Volume Of 12 L Gas After Reducing Pressure
A
12 L
gas confined in a container exerts
3.8 × 10
4
mm Hg
.
If the pressure is reduced to
760 mm Hg
, what will be the
volume
of the gas?
Applying the Ideal Gas Law, we conclude that temperature is kept constant
and there is no mention of moles, i.e. we do not need T, n and R
p
V
=
nRT
,
also called
Boyle's Law
so let's set up a pV ratio for this gas
(
p
initial
)(
V
initial
) = (
p
final
)(
V
final
)
(3.8 × 10
4
mm Hg
)(12.00
L
) = (760
mm Hg
) (
L
)
(3.8 × 10
4
mm Hg
)(12.00
L
)
/
(760
mm Hg
)
= (
x
)
x
= 600
L
The final volume of this gas is 6.0 x 10
2
L