Academic Subjects
Chemistry
General Chemistry
Gases
Calculating Volume Of 0.023 Mole "Dry" Hydrogen At STP

If a metal reacts with a strong acid at 25 ℃ and produces 0.023 mole of H2,
what is the volume of "dry" hydrogen at STP?



To find the volume of dry hydrogen at STP, we want to apply the Ideal Gas Law

pV = nRT

where R = 0.082057 L atm mol-1 K-1

Let's take a quick look at what STP means
Standard Temperature (0 °C = 32 °F = 273.15 K)
&
Standard Pressure (1 atm)

dry hydrogen means pure hydrogen, i.e. hydrogen only

25 °C is the T at which this metal reacts with acid,
i.e. useless info for solving this problem


And we're ready to fill in our values

(1 atm)(V) = (0.023 moles)
(0.082057 L atm) /                mole K
(273.15 K)

(1 atm)(V) = (0.5155189 L atm)

(V) =
(0.5155189 L atm) / (1 atm)


(V) = 0.5155189 L


The volume of dry H2 at STP is 5.2 x 10-1 L