Academic Subjects
Chemistry
General Chemistry
Gases
Calculating Moles Of 2.50 L Nitrogen Gas At 100 °C & 700 mm Hg

The number of moles in 2.50 L of nitrogen gas at 100 °C and 700 mm Hg is

A. 57.1
B. 2.11
C. 0.280
D. 0.0752



Applying the Ideal Gas Law, we first want to check if all units match
R 0.082057 L atm mol-1 K-1

We will have to convert our temperature value
100.00 °C + 273.15 = 373.15 K

and our pressure from mm Hg to atm

700 mm Hg =
1 atm / 760 mm Hg
= 0.921 atm



Now, we're ready for pV = nRT

(0.921 atm)(2.50 L) = (x)
(0.082057 L atm) /             mole K
(373.15 K)

(0.921 atm)(2.5 L) = (x)
(30.6195 L atm) / mole


(x) =
(2.5 L)(0.921 atm) / (30.6195 L atm mole-1)


x = 0.07519 moles


The number of moles is 0.0752
Answer D is the correct option