Academic Subjects
➤
Chemistry
➤
General Chemistry
➤
Gases
➤
Calculating Moles Of 2.50 L Nitrogen Gas At 100 °C & 700 mm Hg
The number of moles in
2.50 L
of nitrogen gas at
100 °C
and
700 mm Hg
is
A. 57.1
B. 2.11
C. 0.280
D. 0.0752
Applying the Ideal Gas Law, we first want to check if all units match
R 0.082057
L
atm
mol
-1
K
-1
We will have to convert our temperature value
100.00 °C
+ 273.15 =
373.15 K
and our pressure from mm Hg to atm
700
mm Hg
=
1
atm
/
760
mm Hg
= 0.921
atm
Now, we're ready for
p
V
=
n
R
T
(0.921
atm
)(2.50
L
) = (
x
)
(0.082057
L
atm
)
/
mole
K
(373.15
K
)
(0.921
atm
)(2.5
L
) = (
x
)
(30.6195
L
atm
)
/
mole
(
x
) =
(2.5
L
)(0.921
atm
)
/
(30.6195
L
atm
mole
-1
)
x
= 0.07519
moles
The number of moles is 0.0752
Answer D is the correct option