Imagine that you have a 6.00 L gas tank and a 4.00 L gas tank.
You need to fill one tank with oxygen and the other with acetylene to use in conjunction with your welding torch.
If you fill the larger tank with oxygen to a pressure of 156 bar, to what pressure should you fill the acetylene tank to ensure
that you run out of each gas at the same time? Assume ideal behavior for all gases.
Applying the Ideal Gas Law, we conclude that temperature is kept constant and there is no mention of moles, i.e. we do not need T, n and R
pV = nRT, also called Boyle's Law
so let's set up a pV ratio between the two gases
(poxygen)(Voxygen) =
(pacetylene)(Vacetylene)
(150 bar)(6.00 L) = (pacetylene)
(4.00 L)
(150 bar)(6.00 L)/(4.00 L)
= (pacetylene)
(pacetylene) = 225 bar
The acetylene tank should have a pressure of 225 bar