Academic Subjects
Chemistry
General Chemistry
Composition
Finding The Emperical Formula

Elemental analysis of a compound showed that it consisted of 54.53% carbon, 9.15% hydrogen and 36.32% oxygen

How many hydrogens appear in the empirical formula of the compound?

A) 2
B) 4
C) 6
D) 9



When dealing with percentages, then 100% =
all of the compound and we therefore set this equal to 100 g

  54.53 g C
+   9.15 g H
+ 36.32 g O
100 g


formula



First, we'll convert grams to moles

(54.53 g C) / 1
(1 mole C) / (12.01 g C)
= 4.54038 moles C
  (9.15 g H) / 1
  (1 mole H) / (1.01 g H)
= 9.05941 moles H

(36.32 g O) / 1
(1 mole O) / (16.00 g O)
= 2.27 moles O

And now, we'll divide the moles of each
element by the smallest number of moles

C =
(4.54038 moles) / (2.27 moles)
= 2.00016 ~ 2

H =
(9.05941 moles) / (2.27 moles)
= 3.9909 ~ 4

O =
(2.27 moles) / (2.27 moles)
= 1

compound




Emperical Formula
C2H4O1

Answer: B